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The videos.list method with the mostPopular chart allows you to specify a maxResults parameter, which has an upper limit of 50 per page. To fetch more than 50, you must use pagination by implementing the pageToken parameter in your requests.
To fetch top videos, you'll use the YouTube API's videos.list method. You'll need to specify the following parameters:
Never hardcode keys into your source code. Use .env files. youtube api keyxml download top
if response.status_code == 200: return response.json() else: print(f"Error: response.status_code - response.text") return None
: Navigate to the Credentials tab, click Create Credentials , and select API Key . A unique string will be generated for you to copy. The videos
try: response = requests.get(endpoint, params=params) response.raise_for_status() return response.json() except requests.exceptions.RequestException as e: print(f"Error al llamar a la API: e") return None
with open(filename, "w", newline="", encoding="utf-8") as f: if csv_data: writer = csv.DictWriter(f, fieldnames=csv_data[0].keys()) writer.writeheader() writer.writerows(csv_data) print(f"✅ Datos guardados en filename") You'll need to specify the following parameters: Never
A structured file format used to store and transport data. While the modern YouTube Data API (v3) primarily defaults to JSON (JavaScript Object Notation), many legacy systems, RSS feeds, and specific software environments still require converting this data into XML format for downloading and parsing.
Use pagination: the response includes a nextPageToken field. Pass this token in subsequent requests with the pageToken parameter to fetch the next page.
Last updated: June 2026. Based on YouTube Data API v3 documentation.
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